","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" ","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" None the these","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":"
","position":1,"answerExplanation":{"@type":"Comment","text":"
$$ \\\\ $$ Given that $$ {\\text{x}} = {\\cos^{ - 1}}\\dfrac{y}{3},{\\text{ }}x \\in \\left[ {0,\\pi } \\right] \\\\ \\Rightarrow y = 3\\cos x \\\\ $$
$$ \\\\ $$ We can observe these points in the graph given in the option $$(b)$$.","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Graphing inverse trigonometric functions Quiz 1","text":" Identify the correct graph of the function $${\\tan^{ - 1}}2x$$.","comment":{"@type":"Comment","text":" By using ${\\tan^{ - 1}}2x$ to make a table and construct the graph."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":"
","position":0},{"@type":"Answer","encodingFormat":"text/html","text":"
","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" None of the above ","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":"
","position":1,"answerExplanation":{"@type":"Comment","text":"
$$ \\\\ $$ Given $$\\tan^{ - 1}2x $$ $$ \\\\ $$ Apply $$x = 0$$, $$\\dfrac{\\pi }{6},\\dfrac{\\pi }{3}........2\\pi \\\\ $$
","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Graphing inverse trigonometric functions Quiz 1","text":" Choose the graph of the function: $$4{\\tan^{ - 1}}\\left( {\\dfrac{{\\cos x - \\sin x}}{{\\cos x + \\sin x}}} \\right)$$.","comment":{"@type":"Comment","text":" To simplify ,divide denominator and numerator by $\\cos x$ and then apply formula $\\tan \\left( {A - B} \\right) = \\dfrac{{\\tan A - \\tan B}}{{1 - \\tan A\\tan B}}$."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":"
","position":0},{"@type":"Answer","encodingFormat":"text/html","text":"
","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" None of the above","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":"
","position":2,"answerExplanation":{"@type":"Comment","text":"
$$ \\\\ $$
$$ \\\\ \\Rightarrow y = 4{\\tan^{ - 1}}\\left( {\\dfrac{{\\cos x - \\sin x}}{{\\cos x + \\sin x}}} \\right) \\\\ $$ Divide by $$\\cos x$$ in denominator and numerator $$ \\\\ \\Rightarrow y = 4{\\tan^{ - 1}}\\left( {\\dfrac{{1 - \\tan x}}{{1 + \\tan x}}} \\right) \\\\ \\Rightarrow y = 4{\\tan^{ - 1}}\\left[ {\\tan \\left( {\\dfrac{\\pi }{4} - x} \\right)} \\right] \\\\ \\Rightarrow y = 4\\left( {\\dfrac{\\pi }{4} - x} \\right) \\\\ \\Rightarrow y = \\pi - 4x \\\\ $$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Graphing inverse trigonometric functions Quiz 1","text":" What is the maximum value of $$y$$ on the graph $$y = {\\tan^{ - 1}}\\dfrac{1}{{\\sqrt {{x^2} - 1} }}$$?","comment":{"@type":"Comment","text":" Apply $x = \\text{cosec}\\theta $ then further and make the table to see the maximum value."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$\\dfrac{\\pi }{2}$$","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$\\dfrac{{3\\pi }}{2}$$","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" None of the above","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$\\dfrac{\\pi }{6}$$","position":0,"answerExplanation":{"@type":"Comment","text":"$$ \\Rightarrow {\\tan^{ - 1}}\\dfrac{1}{{\\sqrt {{x^2} - 1} }} \\\\ {\\text{Let }}\\text{cosec}\\theta = x \\\\ \\theta = \\cos e{c^{ - 1}}x \\\\ \\Rightarrow {\\tan^{ - 1}}\\left( {\\dfrac{1}{{\\sqrt {\\cos e{c^2}\\theta - 1} }}} \\right) \\\\ \\Rightarrow {\\tan^{ - 1}}\\left( {\\dfrac{1}{{\\cot \\theta }}} \\right) \\\\ \\Rightarrow {\\tan^{ - 1}}\\left( {\\tan \\theta } \\right) \\\\ \\Rightarrow \\theta \\\\ $$
$$ \\\\ $$ Thus the maximum value is at $$\\dfrac{\\pi }{6}$$.","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Graphing inverse trigonometric functions Quiz 1","text":" Determine the range where the curve $$y = \\sec x$$ is increasing in the interval $$0 \\leqslant x \\leqslant \\pi $$.","comment":{"@type":"Comment","text":" Apply $x = 0$, $\\dfrac{\\pi }{6}$, $\\dfrac{\\pi }{4}$, $\\dfrac{\\pi }{3}$, $\\dfrac{\\pi }{2}$, $\\pi $ to find the values of $y$ and determine where the function is increasing."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$\\left( {\\dfrac{\\pi }{6},\\dfrac{\\pi }{4}} \\right)$$","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$\\left( {\\dfrac{\\pi }{3},\\dfrac{\\pi }{2}} \\right)$$","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" $$\\left( {\\dfrac{\\pi }{2},\\pi } \\right)$$","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$\\left( {\\dfrac{\\pi }{4},\\dfrac{\\pi }{3}} \\right)$$","position":1,"answerExplanation":{"@type":"Comment","text":"$${\\text{Given }}y = \\sec x \\\\ 0 \\leqslant x \\leqslant \\pi \\\\ $$ Now, we will determine the values of $$y$$ for different values of $$x$$ in the given interval. $$ \\\\ $$
$$ \\\\ $$ From this we can say that the given function is increasing in the interval $$\\left( {\\dfrac{\\pi }{4},\\dfrac{\\pi }{3}} \\right)$$.","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}