Solubility equilibrium Quiz 1

Question 1

We know that when a sparingly soluble salt is dissolved in water, there is the formation of equilibrium between reactant and product. Among which of the following options, correct reactant and product for the equilibrium are mentioned?

Accepted Answer

Ions of salt and undissolved salt

Answer

Ions of salt and solvent

Answer

Ions of salt and dissolved salt

Answer

None of these

Question 2

Sparingly soluble salt when dissolved in water dissociates into ions. So, we can calculate the solubility of ions and the number of ions dissociated. We can use this data to find __.

Accepted Answer

Solubility product

Answer

Solubility constant

Answer

Ionic constant

Answer

Ionic product

Question 3

You are given a reaction: $$ \ C{{D}_{2}}ightleftharpoons {{C}^{+}}+2{{D}^{-}} \ $$  The solubility product of $$C{{D}_{2}}$$ is $$x$$ mole/liter. The solubility $$s$$ will be:

Accepted Answer

$$\frac{{{x}^{1/3}}}{4}$$

Answer

$$2x$$

Answer

$$\frac{{{x}^{1/2}}}{4}$$

Answer

$$4{{x}^{2}}$$

Question 4

In the table given below, 4 sparingly soluble salts with $${{K}_{sp}}$$ are given, find the salt that will have more concentration in the undissociated form : $$ \ $$ <img  src="https://cmds-vedantu.s3.ap-southeast-1.amazonaws.com/prod/question-sets/3ac7d175-7535-4f9f-95a4-16761f8a0f6a7826655990955713820.png"/>

Accepted Answer

4

Answer

3

Answer

2

Answer

1

Question 5

For which of the following compounds we cannot calculate the solubility product but we can calculate the ionic product? $$ \ NaCl,	ext{ }AgCl,	ext{ }AgBr,	ext{ }CuCl$$

Accepted Answer

$$NaCl$$

Answer

$$AgCl$$

Answer

$$CuCl$$

Answer

$$AgBr$$