","comment":{"@type":"Comment","text":" $Molarity(M)=\\dfrac{W}{MW}\\times \\dfrac{1000}{V(ml)} \\\\ $ W = Weight of the chemical $ \\\\ $ MW = Molecular weight of the chemical $ \\\\ $ V = Volume of the solution in ml."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 5 M","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" 20 M","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" None of the above","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 2 M","position":1,"answerExplanation":{"@type":"Comment","text":"$$ \\text{Weight of the calcium carbonate =20 g}\\\\ \\text{Molecular weight of the calcium carbonate = 100} \\\\ \\text{Volume of the solution = 100 ml}\\\\ \\text{Molarity of the solution = ?}\\\\ \\text{Molarity}(M)=\\dfrac{W}{MW}\\times \\dfrac{1000}{V(ml)} \\\\ M=\\dfrac{20}{100}\\times \\dfrac{1000}{100} \\\\ M=2M $$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Molarity Quiz 1","text":" The molarity of a sugar solution is $$2.18 M$$. Find the mass of the sugar which is present in $$250 ml$$ of the water? $$\\text{(Molecular weight of the sugar is 342 amu.)}$$","comment":{"@type":"Comment","text":" $Molarity(M)=\\dfrac{W}{MW}\\times \\dfrac{1000}{V(ml)} \\\\ $ W = Weight of the chemical $ \\\\ $ MW = Molecular weight of the chemical $ \\\\ $ V = Volume of the solution in ml"},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 195.38 g","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" 205.00 g","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" 258.00 g","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 186.55 g","position":0,"answerExplanation":{"@type":"Comment","text":"$$ \\text{W = Weight of the chemical = ?}\\\\ \\text{MW = Molecular weight of the chemical = 342 amu}\\\\ \\text{ V = Volume of the solution in ml = 250 ml}\\\\ \\text{M = Molarity of the solution = 2.18 M}\\\\ Molarity(M)=\\dfrac{W}{MW}\\times \\dfrac{1000}{V(ml)} \\\\ W=\\dfrac{M\\times MW\\times V}{1000} \\\\ W=\\dfrac{2.18\\times 342\\times 250}{1000} \\\\ =186.55g $$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}