Angular momentum Quiz 1

Question 1

A concept that comes from angular momentum, but actually it is not an angular momentum.What is it?

Accepted Answer

Magnetism

Answer

Force

Answer

Orbital motion

Answer

Circular motion

Question 2

What of the following holds true for angular momentum of an electromagnetic wave?

Accepted Answer

Both a and b follows

Answer

It involves dual constituents

Answer

One constituent is spin angular momentum

Answer

Both a and b are wrong

Question 3

A long rod having length $$l$$ and mass $$m$$ lies on supports at its ends. The right support is quickly removed. What is the coercion from the left support immediately thereafter?<img  src="https://cmds-vedantu.s3.ap-southeast-1.amazonaws.com/prod/question-sets/21e6d4ed-b4c2-4a55-92f7-194ac77f3b5f2839859927429162180.png"/>

Accepted Answer

$$2a=\dfrac{3g}{2}$$

Answer

$$mg\dfrac{l}{2}=\left( \dfrac{m{{l}^{2}}}{3} \right)\alpha $$

Answer

$$\alpha =\dfrac{3g}{2l}$$

Answer

$$mg-F=ma$$

Question 4

A tubular slab of mass $$m$$, radius $$r$$, and moment of Inertia $$I=\dfrac{1}{2}m{{r}^{2}}$$ pivots without slipping down a plane inclined at an angle $$	heta $$. What is the gain in propulsion of the center of the slab?<img  src="https://cmds-vedantu.s3.ap-southeast-1.amazonaws.com/prod/question-sets/122a30cf-507c-49cf-a527-2b998891c9c54754413964570684016.png"/>

Accepted Answer

$$v=\sqrt{\left( \dfrac{4}{3} ight)gd.\sin 	heta }$$

Answer

$$\omega =\dfrac{v}{r}$$

Answer

$$\dfrac{m{{v}^{2}}}{2}+\dfrac{I{{\omega }^{2}}}{2}$$

Answer

$$v=\omega r$$

Question 5

A hammer having mass $$m$$ and length $$l$$ is made to hit a rod. The blow is made perpendicular to the rod at one end. Assume the blow occurs quickly, so that the rod doesn’t have time to move much while the hammer is in contact. If the $$CM$$ of the rod ends up moving at speed $$v$$, what will be the pace of the ends right after the blow?

Accepted Answer

$$v+3v=4v$$

Answer

$$\omega =\dfrac{6v}{l}$$

Answer

$$\left( \dfrac{m{{l}^{2}}}{12} \right)\omega =\left( \dfrac{l}{2} \right)mv$$

Answer

$$\Delta L=\left( \dfrac{l}{2} \right)\Delta p$$