","comment":{"@type":"Comment","text":" Find the intersecting points of the graph with x-axis."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$0,\\;1,\\;2$$ ","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$ - 1,\\;0,\\;2$$ ","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" None of these","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$ - 1,\\;2,\\;4$$ ","position":2,"answerExplanation":{"@type":"Comment","text":"Since the graph is intersecting x-axis at $$x = - 1,\\;x = 2\\;{\\text{and}}\\;x = 4$$ $$ \\\\ $$ So $$ - 1,\\;2,\\;4$$ will be the roots of the equation.","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Graphing cube root functions Quiz 1","text":" If the green line in the graph is representing the equation $$y = {x^3}$$ then the equation represented by the blue line will be $$ \\\\ $$ ","comment":{"@type":"Comment","text":" Vertical shifting of a graph make changes in the y-coordinate only. Upward shifting subtracts a constant from the y-coordinate whereas downwards adds."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$y = {\\left( {x - 5} \\right)^3}$$ ","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$y = {\\left( {x + 5} \\right)^3}$$","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$y = {x^3} - 5$$ ","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$y = {x^3} + 5$$","position":2,"answerExplanation":{"@type":"Comment","text":" We can easily see that the parent function of the equation represented by the blue line is a cube root function because it is similar to the green line just shifted upwards by five units. $$ \\\\ $$ And we know that when a graph is vertically shifted it adds or subtract constant $$($$the unit by it is shifted$$)$$ to or from every y-coordinate. $$ \\\\ $$ Since the graph is shifted vertically upwards so the constant $$($$which is $$5$$ here$$)$$ will be subtracted from the y-coordinate in the equation of the parent equation of the graph as follows $$ \\\\ \\Rightarrow \\left( {y - 5} \\right) = {x^3} \\\\ \\Rightarrow y = {x^3} + 5 $$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Graphing cube root functions Quiz 1","text":" Find the center point of the function $$y = \\sqrt[3]{{x + 1}} - 9$$ ","comment":{"@type":"Comment","text":" First convert the equation into standard form and then equate them with zero.\t"},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$\\left( {1,\\;9} \\right)$$ ","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$\\left( { - 1,\\;9} \\right)$$","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$\\left( {1,\\; - 9} \\right)$$ ","position":2}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$\\left( { - 1,\\; - 9} \\right)$$ ","position":3,"answerExplanation":{"@type":"Comment","text":"Parent function of the given function is $$y = \\sqrt[3]{x}$$ $$ \\\\ $$ The given function $$y = \\sqrt[3]{{x + 1}} - 9$$ as $$\\left( {y - 9} \\right) = \\sqrt[3]{{\\left( {x + 1} \\right)}}$$ $$ \\\\ $$ And assuming $$y + 9 = Y\\;{\\text{and}}\\;x + 1 = X$$ $$ \\\\ $$ Now, the new center is $$ \\\\ \\Rightarrow \\left( {X,\\;Y} \\right) \\equiv \\left( {0,\\;0} \\right) \\\\ \\Rightarrow \\left( {x + 1,\\;y + 9} \\right) \\equiv \\left( {0,\\;0} \\right) \\\\ \\Rightarrow x + 1 = 0\\;{\\text{and}}\\;y + 9 = 0 \\\\ \\Rightarrow x = - 1\\;{\\text{and}}\\;y = - 9 $$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Graphing cube root functions Quiz 1","text":" Draw the graph of the equation $$y = {\\left( {x - 5} \\right)^3}$$ ","comment":{"@type":"Comment","text":" Addition or subtraction with x-coordinate shifts the parent graph to the left or right respectively."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":"
","position":1},{"@type":"Answer","encodingFormat":"text/html","text":"
","position":2},{"@type":"Answer","encodingFormat":"text/html","text":"
","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":"
","position":0,"answerExplanation":{"@type":"Comment","text":"The parent function of the function $$y = {\\left( {x - 5} \\right)^3}$$ is $$y = {x^3}$$ $$ \\\\ $$ In the equation $$y = {\\left( {x - 5} \\right)^3}$$ change is only with x-coordinate $$ \\\\ $$ And when there is a constant subtracted from the x-coordinate then we shift the graph to the right by constant units. $$ \\\\ $$ So if we shift the graph of $$y = {x^3}$$ to five units rightward then we will get the graph of $$y = {\\left( {x - 5} \\right)^3}$$ i.e. $$ \\\\ $$
","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Graphing cube root functions Quiz 1","text":" Graph of the cube root function $$y = \\sqrt[3]{{x - 11}} + 12$$ can be drawn by shifting the graph of $$y = \\sqrt[3]{x}$$ ","comment":{"@type":"Comment","text":" Subtraction of a constant from any axes shifts the graph constant units to the positive side."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$11$$ units to the right and $$12$$ units upward","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$11$$ units to the left and $$12$$ units downward","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" $$11$$ units to the right and $$12$$ units downward","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$11$$ units to the left and $$12$$ units upward","position":0,"answerExplanation":{"@type":"Comment","text":"We have $$ \\\\ \\Rightarrow y = \\sqrt[3]{{x - 11}} + 12 \\\\ \\Rightarrow y - 12 = \\sqrt[3]{{x - 11}} $$ $$ \\\\ $$ On comparing the equation with parent function $$y = \\sqrt[3]{x}$$, then we get that $$12$$ is being subtracted from $$y$$ and $$11$$ is also being subtracted from $$x$$ $$ \\\\ $$ And when a constant is being subtracted from $$y$$ then the graph shifts vertically upwards and when a constant is subtracted from $$x$$ the graph shifts to the left. $$ \\\\ $$ Therefore we can get the graph of $$y = \\sqrt[3]{{x - 11}} + 12$$ by shifting the graph of $$y = \\sqrt[3]{x}$$ to $$11$$ units to the left and $$12$$ units upward.","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}