","comment":{"@type":"Comment","text":" Check the similarity of both triangles using different criteria. Using the corresponding side ratios, find BD . The AAA and AA criterion is the same as if two angles of two triangles are equal then the third angles also become equal. "},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" SAS, 4cm","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" AAA, 4cm","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" RHS, 8cm","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" AA, 8cm","position":0,"answerExplanation":{"@type":"Comment","text":" $$\\text{In }\\Delta ABD \\text{ and } \\Delta EBC \\\\ \\text{All the angles of triangles are the same}\\\\ \\text{Thus by AAA criterion both the triangles are similar.} \\\\ \\therefore, \\dfrac{BE}{BC}=\\dfrac{AB}{BD} \\\\ \\text{Given, } AE = 3cm, EB = 3cm, BC = 4cm \\\\ \\text{So, }AB = AE + EB = 6cm \\\\ \\therefore, \\dfrac{BE}{BC}=\\dfrac{AB}{BD} \\\\ \\Rightarrow \\dfrac{3}{4}=\\dfrac{6}{BD} \\\\ \\Rightarrow BD=\\dfrac{6\\times 4}{3}=8cm $$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Triangle similarity Quiz 1","text":" A building casts a 100-foot shadow at the same time that a 40-foot flagpole casts as 20 foot shadow. How tall is the building? $$\\text{(Round off to nearest integer)}$$","comment":{"@type":"Comment","text":" For such a question, it is always considered that $\\angle A=\\angle D=\\theta $. Use trigonometric ratios to find relations between the sides of the triangles and find AB. "},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 205ft","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" 195ft","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" 203ft","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 200ft","position":1,"answerExplanation":{"@type":"Comment","text":" $$ \\\\ \\text{Let the height of the building be AB and its shadow length be BC.} \\\\ \\text{Let the height of the flagpole be DE and its shadow length be EF.} \\\\ \\text{Given, }BC = 100ft, DE = 40ft, EF = 20ft \\\\ \\text{Here, it is considered that }\\angle A=\\angle D=\\theta \\\\ \\text{Now in }\\Delta ABC \\text{ and } \\Delta DEF, \\\\ \\angle A=\\angle D \\\\ \\angle ABC=\\angle DEF=90{}^\\circ \\\\ \\text{So, by AA criterion, }\\Delta ABC \\text{ and } \\Delta DEF \\text{ are similar.} \\\\ \\therefore \\dfrac{BC}{AB}=\\dfrac{EF}{DE} \\\\ \\Rightarrow \\dfrac{100}{AB}=\\dfrac{20}{40} \\\\ \\Rightarrow AB=\\dfrac{100\\times 40}{20}=200ft$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Triangle similarity Quiz 1","text":" Find the ratio of area of $$\\Delta BED$$ and $$\\Delta ABC$$ given that $$AC||ED \\\\ $$
","comment":{"@type":"Comment","text":" Parallel lines generate corresponding angles which are equal. Prove both the triangles to be similar and use this formula: Ratio of area of the $\\Delta $BED and $\\Delta $ABC=$\\left( {} \\right.$Ratio of corresponding sides${{\\left. {} \\right)}^{2}}$"},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $${{\\left( \\dfrac{BE}{AD} \\right)}^{2}}$$","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $${{\\left( \\dfrac{BE}{AC} \\right)}^{2}}$$","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" $${{\\left( \\dfrac{ED}{DB} \\right)}^{2}}$$","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $${{\\left( \\dfrac{BE}{AB} \\right)}^{2}}$$","position":1,"answerExplanation":{"@type":"Comment","text":" $$\\text{In }\\Delta BED \\text{ and } \\Delta ABC, \\\\ \\angle B\\text{ common} \\\\ \\angle BED=\\angle BAC\\text{ } \\\\ \\angle BDE=\\angle BCA \\\\ \\text{Above are the corresponding Angles }\\\\ \\text{So, by AA criterion }\\Delta BED \\text{ and } \\Delta ABC \\text{ are similar.} \\\\ \\text{Ratio of area of the }\\Delta BED \\text{ and } \\Delta ABC = \\left( {} \\right. \\text{Ratio of corresponding sides } {{\\left. {} \\right)}^{2}} \\\\ \\text{Thus, the ratio of area of the }\\Delta BED \\text{ and } \\Delta ABC = {{\\left( \\dfrac{BE}{AB} \\right)}^{2}}$$ ","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Triangle similarity Quiz 1","text":" A line parallel to AC is drawn meeting AB at point E from D. Find the length of AE if it is known that, $$\\dfrac{BD}{BC}=\\dfrac{1}{2}$$, AB$$=$$6 cm, BD$$=$$6cm
","comment":{"@type":"Comment","text":" Draw a line parallel to AC, then prove that both the triangles are similar to each other. Then by using the ratio of corresponding sides, find the value of AB. Use basic arithmetic, to find AE from AB."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 6cm","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" 2cm","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" 4cm","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 3cm","position":2,"answerExplanation":{"@type":"Comment","text":" $$\\text{Draw a line parallel to AC i.e., ED.} \\\\ $$
$$ \\\\ \\text{In }\\Delta BED \\text{ and } \\Delta ABC \\\\ \\angle B\\text{ common} \\\\ \\angle BED=\\angle BAC\\text{ } \\\\ \\angle BDE=\\angle BCA \\\\ \\text{Above are the corresponding Angles }\\\\ \\text{So, by AA criterion }\\Delta BED \\text{ and } \\Delta ABC \\text{ are similar.} \\\\ \\therefore \\dfrac{BD}{BC}=\\dfrac{BE}{AB} \\\\ \\Rightarrow \\dfrac{1}{2}=\\dfrac{BE}{6} \\\\ \\Rightarrow BE=3cm \\\\ AB=EB+EA \\\\ 6=3+EA \\\\ AE=3cm $$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}