","comment":{"@type":"Comment","text":" The equation used is: ${{M}_{1}}{{V}_{1}}={{M}_{2}}{{V}_{2}}$"},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 0.6 M","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" 0.9M","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" 0.5M","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 0.4M","position":0,"answerExplanation":{"@type":"Comment","text":"When the volume increases then the molarity decreases. The equation used is $${{M}_{1}}{{V}_{1}}={{M}_{2}}{{V}_{2}}.\\\\ $$ The volume of the mixture of $$NaBr$$ and $$KCl$$ formed is 180mL. $$ \\\\ $$ The volume of KCl is 120ml. So the volume increased by less than a factor of 2. $$ \\\\ $$ So the molarity also decreases by a factor of 2 only. $$ \\\\ 120\\times 0.6={{M}_{2}}\\times 180\\\\ {{M}_{2}}=0.4M$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}