Question

Given, $$\mathrm{\Delta }G{}^{\circ }=-nFE{}^{\circ }cell$$ ​ and $$\mathrm{\Delta }G{}^{\circ }=-RTlnk$$. The value of $$n=2$$ will be given by the slope of which line in the figure?

Answer 1

Hint: We know that the delta G that is measured in the question is known as Gibbs Energy. We need to know the formula of Gibbs energy, in relation to the concentration of the electrolytic cell. Gibbs energy change refers to the thermodynamic potential that is used to evaluate the highest reversible work done by a thermodynamic system at constant pressure and temperature.

Complete step by step solution:
Enthalpy is defined as the heat content of a system at constant pressure. Chemists routinely measure changes in the enthalpy of chemical systems. As reactants are converted into products the heat is absorbed or released by a reaction at constant pressure is the same as that of the enthalpy change. Entropy measures the level of disorder in a thermodynamics system. The entropy of a substance can be obtained by measuring the heat which is required to raise the temperature to a given amount using a reversible process.
As we know that $$\mathrm{\Delta }G{}^{\circ }=-nFE{}^{\circ }cell=-RT\ln k$$ or $$E{}^{\circ }cell={\displaystyle \frac{RT}{nF}}\ln k$$
By plot $\ln k$ or $$E{}^{\circ }cell$$ will be having slope of ${\displaystyle \frac{1}{2}}{\displaystyle \frac{RT}{F}}$
Thus, Slope, $m={\displaystyle \frac{RT}{nF}}={\displaystyle \frac{8.314\times 298}{2\times 96500}}=0.0129$
Therefore, line OA since slope is positive but value is less.

Note:
Remember that in thermodynamics, Gibbs free energy is defined as a thermodynamic potential that can be used to calculate the maximum of reversible work that may be performed by a thermodynamics system at a constant temperature and pressure. Gibbs free energy can also be defined in a way where it is represented as a difference between the enthalpy of a system and the product of its entropy and absolute temperature.