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# How does the electric force between two charged objects change?

Last updated date: 25th Jun 2024
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Hint: The attractive and repulsive forces between particles which are caused due to their electric charges is known as the electrostatic force. Conventionally the electric force between stationary charged bodies is known as the electrostatic force. It is also referred to as Coulomb's force.

As we know the electrostatic force between two charged particles is calculated as Coulomb's force as is calculated as
$F = \dfrac{1}{{4\pi {\varepsilon _0}}}\dfrac{{{q_1}{q_2}}}{{{r^2}}}$ or $F = {k_e}\dfrac{{{q_1}{q_2}}}{{{r^2}}}$
Where F is the electrostatic force
${k_e}$is Coulomb's constant and its value is $8.8987 \times {10^9}N{m^2}{C^{ - 2}}$
${q_1}{q_2}$are the charges on the particles
And r is the distance between the particles.
Now here we can see that the electrostatic force (F) depends upon the magnitude of the charges on two particles and inversely depends upon the distance between two charges.
Here it is evident that $F \propto \dfrac{1}{{{r^2}}}$
So, we can conclude here that the electrostatic force (F) is inversely proportional to the square of the distance between two particles. As the distance between two-particles decreases, force between them will increase.

Hence, the electrostatic force (F) depends upon the magnitude of the charges on two particles and inversely proportional to the square of the distance between two charges.

Note:
• The magnitude of the charge should be kept along with its sign.
• The electrostatic charge may be attractive and repulsive depending upon the nature of the charge on the two-body.
• Like charges repel and unlike charges attract each other.