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Mathematics
Solution of linear equations
How do you solve the system $2x - y = 8$ and $x + 2y = 9$

Mathematics
Solution of linear equations
Solve $3(x + 6) + 2(x + 3) = 64$ for the value of $x$ .

Mathematics
Solution of linear equations
How do you solve $\dfrac{{x - 3}}{4} + \dfrac{x}{2} = 3$ ?

Mathematics
Solution of linear equations
Solve the following equation
$\dfrac{1}{2}x - 3 = 5 + \dfrac{1}{3}x$

Mathematics
Solution of linear equations
Solve and check your answer: $\dfrac{2}{3}x + 3 = 11$

Mathematics
Solution of linear equations
Solve the following simultaneous equations for $x\,and\,y$ :
$m(x + y) + n(x - y) - ({m^2} + mn + {n^2}) = 0$
$n(x + y) + m(x - y) - ({m^2} - mn + {n^2}) = 0$
(1) Let $x + y = a,x - y = b$ .
(2) Transfer the terms not containing $x\,and\,y$ to RHS.
(3) Add equations, substitute the value of $a\,and\,b$ and solve.

Mathematics
Solution of linear equations
Find the value of $Q$ in the following system so that the solution to the system is $\left\{ {\left( {x,y} \right):x - 3y = 4} \right\}$?
$x - 3y = 4$
$Qx - 6y = 8$

Mathematics
Solution of linear equations
Given the linear equation $2x + 3y - 8 = 0$, write another linear equation in two variables such that the geometrical representation of the pair so formed is of intersecting lines:
(A) $2x + 3y + 9 = 0$
(B) $6x + 9y + 9 = 0$
(C) $3x + 2y + 9 = 0$
(D) None of these
Mathematics
Solution of linear equations
Five years ago, the father was 7 times that of his son. At present time, the father’s age is 4 times that of his son. Find the present age of son and father?
Mathematics
Solution of linear equations
Solve the following systems of equations by the method of cross-multiplication:
5ax + 6by=28
3ax+ 4by=18

Mathematics
Solution of linear equations
Solve the following pair of equations graphically: $x+y=4$, $3x-2y=-3$
Shade the region bounded by the lines representing the above equation and $x-$axis.
A. $x=3,y=2$
B. $x=1,y=3$
C. $x=8,y=2$
D. $x=9,y=2$
Mathematics
Solution of linear equations
How to solve the following equations?
$$1)5 + x = \dfrac{1}{2} - \dfrac{1}{3}$$,
$$2)\dfrac{1}{4} + x = \dfrac{1}{2} - \dfrac{1}{3}$$,
$$3)1 - \dfrac{1}{2} + m = \dfrac{3}{4} + \dfrac{1}{2}$$.
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