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Mathematics
Equation of tangent of an ellipse
Any ordinate $NP$ of an ellipse meets the auxiliary circle in $Q$; prove that the locus of the intersection of the normals at $P$ and $Q$ is the circle ${{x}^{2}}+{{y}^{2}}={{\left( a+b \right)}^{2}}$.
Mathematics
Equation of tangent of an ellipse
If any tangent to the ellipse $\dfrac{{{x}^{2}}}{{{a}^{2}}}+\dfrac{{{y}^{2}}}{{{b}^{2}}}=1$ intercepts equal length $'l'$ on the axes, then $l$ is equal to
$\left( A \right)\text{ }{{a}^{2}}+{{b}^{2}}$
$\left( B \right)\text{ }\sqrt{{{a}^{2}}+{{b}^{2}}}$
$\left( C \right)\text{ }{{\left( {{a}^{2}}+{{b}^{2}} \right)}^{2}}$
$\left( D \right)\text{None of these}$

Mathematics
Equation of tangent of an ellipse
A tangent to the ellipse ${x^2} + 4{y^2} = 4$ meets the ellipse ${x^2} + 2{y^2} = 6$ at P and Q the tangents at P and Q of the ellipse ${x^2} + 2{y^2} = 6$ is
A. ${90^ \circ }$
B. ${60^ \circ }$
C. ${45^ \circ }$
D. ${30^ \circ }$
Mathematics
Equation of tangent of an ellipse
If a tangent of slope m at a point of the ellipse $\dfrac{{{x}^{2}}}{{{a}^{2}}}+\dfrac{{{y}^{2}}}{{{b}^{2}}}=1$ passes through (2a, 0) and if “e” denotes the eccentricity of the ellipse, then:
(a)${{m}^{2}}+{{e}^{2}}=1$
(b) $2{{m}^{2}}+{{e}^{2}}=1$
(c) $3{{m}^{2}}+{{e}^{2}}=1$
(d)${{m}^{2}}+{{e}^{2}}-2=0$
Mathematics
Equation of tangent of an ellipse
Find the equations of tangent and normal to the ellipse $2{x^2} + 3{y^2} = 11$ at the point whose ordinate is 1.
Mathematics
Equation of tangent of an ellipse
Find the point on the ellipse $4{{x}^{2}}+9{{y}^{2}}=1$ at which tangent is parallel to the line $8x=9y$.
Mathematics
Equation of tangent of an ellipse
Find the equation of tangent to the curve $4{{x}^{2}}+9{{y}^{2}}=36$ at the point $\left( 3\cos \theta ,2\sin \theta \right)$ where $\theta$ is the polar angle.

Mathematics
Equation of tangent of an ellipse
Write the equation of tangent at (1,1) on the curve $2{{x}^{2}}+3{{y}^{2}}=5$.
Mathematics
Equation of tangent of an ellipse
Find equations of tangents drawn to the curve ${y^2}\, - \,2{x^2}\, - \,4y\, + \,8\, = \,0$ from the point $(\,1\,,\,2\,)$.

Mathematics
Equation of tangent of an ellipse
If tangents are drawn to the ellipse ${{x}^{2}}+2{{y}^{2}}=2$ at all points on the ellipse other than its four vertices, then the midpoints of the tangents intercepted between the coordinate axes lie on the curve:
(a) $\dfrac{{{x}^{2}}}{2}+\dfrac{{{y}^{2}}}{4}=1$,
(b) $\dfrac{{{x}^{2}}}{4}+\dfrac{{{y}^{2}}}{2}=1$,
(c) $\dfrac{1}{2{{x}^{2}}}+\dfrac{1}{4{{y}^{2}}}=1$,
(d) $\dfrac{1}{4{{x}^{2}}}+\dfrac{1}{2{{y}^{2}}}=1$.
Mathematics
Equation of tangent of an ellipse
The minimum area of a triangle formed by any tangent to the ellipse $\dfrac{{{x^2}}}{{16}} + \dfrac{{{y^2}}}{{81}} = 1$ and the coordinate axes is
A. $12$
B.$18$
C.$26$
D.$36$

Mathematics
Equation of tangent of an ellipse
The equation of the tangent to the ellipse $4{{x}^{2}}+3{{y}^{2}}=5$ which is parallel to the straight line $y=3x+7$ is
A. $2\sqrt{3}x-6\sqrt{3}y+\sqrt{155}=0$
B. $2\sqrt{3}x-2\sqrt{3}y-\sqrt{155}=0$
C. $6\sqrt{3}x-2\sqrt{3}y+\sqrt{155}=0$
D. $6\sqrt{3}x-2\sqrt{3}y-\sqrt{155}=0$

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