Courses
Courses for Kids
Free study material
Offline Centres
More

Identify X, Y, and Z in the given reaction:
 
(A) ${ X=CH }_{ 2 }{ BrCH }_{ 2 }{ Br }{ ;Y=CH }_{ 3 }{ CH }_{ 2 }{ CH }_{ 2 }{ CN }$
(B) ${ X=CH }_{ 2 }{ BrCH }_{ 2 }{ Br }{ ;Y=CH }_{ 3 }{ CH }_{ 2 }{ CN }$
(C) ${ X=CH }_{ 2 }{ CH }_{ 2 }{ Br }{ ;Y=CH }_{ 3 }{ CH }_{ 2 }{ CN }$
(D) ${ X=CH }_{ 2 }{ BrCH }_{ 2 }{ Br }{ ;Y=NCCH }_{ 3 }{ CH }_{ 2 }{ CN }$

seo-qna
Last updated date: 03rd Mar 2024
Total views: 21k
Views today: 0.21k
Rank Predictor
Answer
VerifiedVerified
21k+ views
Hint:Lithium aluminium hydride acts as a reducing agent.
Carbon tetrachloride is a non-polar solvent. The purpose is to use this inert solvent to dissolve the reactants in the reaction.
Bromination: Any reaction or process in which bromine (and no other elements) are introduced into a molecule.

Complete step by step solution:
> The concept of more substituted and less substituted carbocation is used in addition to H-X (i.e. protonation of the alkenes. But, in direct halogenation like ${ Br }_{ 2 }{ /CCl }_{ 4 }$ medium the bromonium ion attacks at the double bond and a vicinal dihalide i.e. 1,2 product is obtained.
> When ethene reacts with ${ Br }_{ 2 }$ and ${ CCl }_{ 4 }$ then dibromoethane will be formed. So, X will be a dibromo product.
Now, when dibromoethane reacts with NaCN then ${ 1,4-dicyanobutane }$ will be formed. So, Y will be ${ 1,4-dicyanobutane }$.
> Finally, when ${ 1,4-dicyanobutane }$ reacts with lithium aluminium hydride, then ${ 1,4-diaminobutane }$ will be formed. So, Z will be ${ 1,4-diaminobutane }$.
The following reaction will take place;



Hence, the correct option is D.

Note: The possibility to make a mistake is that you may choose option A. When we react with NaCN, then dicyano products will be formed and not just cyanide.