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\[{}_{89}A{c^{227}}\;\] is a member of the actinium series. Another member of the same series is:
(A) \[{}_{92}{U^{235}}\;\]
(B) \[{}_{90}T{h^{232}}\;\]
(C) \[{}_{89}A{c^{225}}\;\]
(D) \[{}_{15}{P^{34}}\;\]
(E) \[{}_{15}{P^{217}}\;\]

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Last updated date: 04th Mar 2024
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Hint-The actinium series in the periodic table is a radioactive series that means all the elements of this series are radioactive. Actinium series is a $4n + 3$series, Hence this shows that when the mass number is divided by four $4$ then remainder will be $3$.

Complete step by step solution:
On checking each option given in the question, we see that,
For option (A) mass number =$235 = 4 \times (58) + 3$
So, the remainder is $3$.
For the option (B) mass number=$232 = 4 \times (58) + 0$
So, the remainder is $0$.
For the option (C) mass number =$225 = 4 \times (56) + 1$
So, the remainder is$1$.
For the option (D) mass number=$34 = 4 \times 8 + 2$
So, the remainder is$2$.
For the option (E) mass number=$217 = 4 \times (54) + 1$
So, the remainder is$1$.
So here we see that the only mass number is $235$which gives the remainder \[3\] on dividing it with $4$. Hence the only \[{}_{92}{U^{235}}\;\]is the member of the actinium series among the all five given options.

So, option (A) is the correct answer.

Note-Actinide series contains the atomic number from 89 to 103. Some properties of the actinium series are as follows-
1- known as rare earth metals.
2- Since they are unstable in nature that’s why they are radioactive metals.
3- Majority synthetically made by the particle accelerators creating nuclear reactions and making them short lasting or unstable. That’s why they have the ability to undergo nuclear reaction.
4- All elements of actinides have the ability to make stable complexes with ligands, such as chloride, sulphur, carbonate and acetate.
5- Many of the actinides are found in nature as sea water or minerals.
6- Actinides when they are radioactive form then on interaction with different types of phosphorus will produce a pulse of light.