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NCERT Solutions for Class 8 Maths Chapter 4: Practical Geometry - Exercise 4.2

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Last updated date: 22nd Mar 2024
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MVSAT 2024

NCERT Solutions for Class 8 Maths Chapter 4 (EX 4.2)

NCERT Solutions for Class 8 Maths Chapter 4 offered by Vedantu provides a better understanding of Geometry from basics to elementary. Vedantu being well known for its quick and easy teaching techniques can make you understand everything related to Geometry hassle-free. So, if you are someone struggling to understand the ABC's of practical Geometry Class 8 Maths, Vedantu's NCERT solution can be your helping hand. these solutions are available for free of cost on Vedantu’s site, which you can download as per your requirement.and also Science Students who are looking for NCERT Solutions for Class 8 Science will also find the Solutions curated by our Master Teachers really Helpful.


Class:

NCERT Solutions for Class 8

Subject:

Class 8 Maths

Chapter Name:

Chapter 4 - Practical Geometry

Exercise:

Exercise - 4.2

Content-Type:

Text, Videos, Images and PDF Format

Academic Year:

2023-24

Medium:

English and Hindi

Available Materials:

  • Chapter Wise

  • Exercise Wise

Other Materials

  • Important Questions

  • Revision Notes

Why Choose NCERT Solutions for Class 8 Maths Chapter 4 Exercise 4.2?

Exercise 4.2

1. Construct the following quadrilaterals.

(i) Quadrilateral LIFT

$LI=4cm$

$IF=3cm$

$TL=2.5cm$

$LF=4.5cm$

$IT=4cm$

Ans:  

STEP 1: Firstly draw a rough sketch of this quadrilateral as follows.


Quadrilateral Lift


STEP 2:  Now, $\vartriangle ITL$ can be constructed by using the given measurement as follows .


Quadrilateral Lift


STEP 3: Now, the vertex F of length $4.5cm$ away from vertex L and 3cm away from vertex I. Therefore, while taking L and I as centres, draw arcs of length $4.5cm$ radius 3cm respectively,  which will be intersecting each other at point F.


Quadrilateral Lift


STEP 4 : Join point F to T and F to I.


Quadrilateral Lift


LIFT is the required quadrilateral.

(ii) Quadrilateral GOLD

$OL=7.5cm$

$GL=6cm$

$GD=6cm$

$LD=5cm$

$OD=10cm$

Ans: 

STEP 1: Firstly, we will  draw a rough sketch of this quadrilateral.


Quadrilateral Gold


STEP 2: Now,  $\vartriangle GDL$ can be constructed by using the given measurements as follows :


Quadrilateral Gold


STEP 3: Now, the vertex O is 10cm away from vertex D and$7.5cm$ away from vertex L. Therefore, while taking D and L as centres, draw arcs of 10cm radius and $7.5cm$ radius respectively. These will intersect each other at point O.


Quadrilateral Gold


STEP 4: Join point O to G and L.


Quadrilateral Gold


GOLD is the required quadrilateral.

(iii) Rhombus BEND

$BN=5.6cm$

$DE=6.5cm$

Ans : In rhombus, we know that the diagonals always bisect each other at $90{}^\circ $.

Let us assume that these are intersecting each other at point O in this rhombus.

Hence,  $EO=OD=3.25cm$.

STEP 1: Firstly , we will draw a rough sketch of the rhombus as follows:


Rhombus BEND


STEP 2: Now, draw a line segment BN of length $5.6cm$ and also draw its perpendicular bisector. Let it intersect the line segment BN at point O.


Rhombus BEND


STEP 3: Now, taking O as centre, draw arcs of $3.25cm$ radius to intersect the perpendicular bisector at point D and E.


Rhombus BEND


STEP 4:  Now, join points D and E to points B and N.


Rhombus BEND


BEND is the required quadrilateral.


Why Choose NCERT Solutions for Class 8 Maths Chapter 4 Exercise 4.2?

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Advantages of NCERT Maths Solutions for Class 8 Chapter 4

Importance of NCERT Solution:

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Quality NCERT Provides:

To make the understanding better and precise is what we do at Vedantu. Hence, we have crafted a bespoke range of questionnaires and solutions for Class 8 maths Chapter 4 so that the student can solve every question without any trouble.


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Everything As Per NCERT Guidelines:

All the solutions and methods into the PDF provided by Vedantu is according to NCERT guidelines.


Why is Geometry Important?

Geometry can help students to boost their knowledge about foundation skills. It also helps to build logical thinking, logical reasoning, analytical reasoning, and increase the problem-solving characteristics of the students. 


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