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NCERT Solutions for Class 8 Maths Chapter 2: Linear Equations in One Variable - Exercise 2.1

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Last updated date: 29th Mar 2024
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MVSAT 2024

NCERT Solutions for Class 8 Maths Chapter 2 (EX 2.1)

NCERT Solutions for Class 8 Maths Chapter 2 provided by Vedantu offers clarifications for the students who can go far but lack the concentration. These solutions help the students to score excellent marks in their exams. If you are a student of Class 8, then this NCERT Solutions for Class 8 Maths Chapter 2 PDF file is beneficial to obtain. All the experts at Vedantu have enough skills and followed CBSE guidelines to create the NCERT Solutions of Class 8, which are available on the site for download. Subjects like Science, Maths, English will become easy to study if you have access to NCERT Solution for Class 8 Science, Maths solutions and solutions of other subjects.


Class:

NCERT Solutions for Class 8

Subject:

Class 8 Maths

Chapter Name:

Chapter 2 - Linear Equations in One Variable

Exercise:

Exercise - 2.1

Content-Type:

Text, Videos, Images and PDF Format

Academic Year:

2023-24

Medium:

English and Hindi

Available Materials:

  • Chapter Wise

  • Exercise Wise

Other Materials

  • Important Questions

  • Revision Notes



Download Class 8 Maths NCERT Solutions to help you to revise complete syllabus ans score more marks in your examinations.

Access NCERT solutions for Maths Chapter 2 – Linear Equations in One Variable

1. Find the solution of \[\text{x-2=7}\].

Ans: We have an equation \[\text{x-2=7}\], to solve the following equation we will shift \[\text{2}\] to right hand side, we get

\[\text{x=7+2}\]

\[\text{x=9}\]

2. Find the solution of \[\text{y+3=10}\].

Ans: We have an equation \[\text{y+3=10}\], to solve the following equation we will shift \[\text{3}\] to right hand side, we get

\[\text{y=10-3}\]

\[\text{y=7}\]

3. Find the solution of \[\text{6=z+2}\].

Ans: We have an equation \[\text{6=z+2}\], to solve the following equation we will shift \[\text{2}\] to left hand side, we get

\[\text{6-2=z}\]

\[\text{z=4}\]

4. Find the solution of \[\frac{\text{3}}{\text{7}}\text{+x=}\frac{\text{17}}{\text{7}}\].

Ans: We have an equation \[\frac{\text{3}}{\text{7}}\text{+x=}\frac{\text{17}}{\text{7}}\], to solve the following equation we will shift \[\frac{\text{3}}{\text{7}}\] to right hand side, we get

\[\text{x=}\frac{\text{17}}{\text{7}}\text{-}\frac{\text{3}}{\text{7}}\]

\[\text{x=}\frac{\text{14}}{\text{7}}\]

\[\text{x=2}\]

5. Find the solution of \[\text{6x=12}\].

Ans: We have an equation \[\text{6x=12}\], to solve the following equation, we will shift \[6\] to right hand side and divide \[12\] by \[6\], we get

\[\text{x=}\frac{\text{12}}{6}\]

\[\text{x=2}\]

6. Find the solution of \[\frac{\text{t}}{\text{5}}\text{=10}\].

Ans: We have an equation \[\frac{\text{t}}{\text{5}}\text{=10}\], to solve the following equation, we will shift \[5\] to right hand side and multiply \[10\] by \[5\], we get

\[\text{t=10}\times \text{5}\]

\[\text{t=50}\]

7. Find the solution of \[\frac{\text{2x}}{\text{3}}\text{=18}\].

Ans: We have an equation \[\frac{\text{2x}}{\text{3}}\text{=18}\], to solve the following equation, we will multiply both sides of equation by \[\frac{\text{2}}{\text{3}}\] , we get

\[\text{x=}\frac{\text{18 }\!\!\times\!\!\text{ 3}}{\text{2}}\]

\[\text{x=27}\]

8. Find the solution of \[\text{1}\text{.6=}\frac{\text{y}}{\text{1}\text{.5}}\].

Ans: We have an equation \[\text{1}\text{.6=}\frac{\text{y}}{\text{1}\text{.5}}\], to solve the following equation, we will multiply both sides of equation by \[1.5\] , we get

\[\text{1}\text{.6 }\!\!\times\!\!\text{ 1}\text{.5=y}\]

\[\text{y=2}\text{.4}\]

9. Find the solution of \[\text{7x-9=16}\].

Ans: We have an equation \[\text{7x-9=16}\], to solve the following equation we will shift \[\text{9}\] to right hand side, we get

\[\text{7x=16+9}\]

\[\text{7x=25}\]

Now, we will divide both sides by \[\text{7}\], we get

\[\text{x=}\frac{\text{25}}{\text{7}}\]

10. Find the solution of \[\text{14y-8=13}\].

Ans: We have an equation \[\text{14y-8=13}\], to solve the following equation we will shift \[\text{8}\] to right hand side, we get

\[\text{14y=13+8}\]

\[\text{14y=21}\]

Now, we will divide both sides by \[\text{14}\], we get

\[\text{x=}\frac{\text{21}}{\text{14}}\]

\[\text{x=}\frac{\text{3}}{\text{2}}\]

11. Find the solution of \[\text{17+6p=9}\].

Ans: We have an equation \[\text{17+6p=9}\], to solve the following equation we will shift \[\text{17}\] to right hand side, we get

\[\text{6p=9-17}\]

\[\text{6p=-8}\]

Now, we will divide both sides by \[\text{6}\], we get

\[\text{p=-}\frac{\text{8}}{\text{6}}\]

\[\text{p=-}\frac{\text{4}}{\text{3}}\]

12. Find the solution of \[\frac{\text{x}}{\text{3}}\text{+1=}\frac{\text{7}}{\text{15}}\].

Ans: We have an equation \[\frac{\text{x}}{\text{3}}\text{+1=}\frac{\text{7}}{\text{15}}\], to solve the following equation we will shift \[\text{1}\] to right hand side, we get

\[\frac{\text{x}}{\text{3}}\text{=}\frac{\text{7}}{\text{15}}\text{-1}\]

\[\frac{\text{x}}{\text{3}}\text{=-}\frac{\text{8}}{\text{15}}\]

Now, we will multiply both sides by \[\text{3}\], we get

\[\text{x=-}\frac{\text{8 }\!\!\times\!\!\text{ 3}}{\text{15}}\]

\[\text{x=-}\frac{\text{8}}{\text{5}}\]

Why Choose NCERT Solutions for Class 8 Maths Chapter 2?

Math can be very tricky and hard to perform. It gets better with practice. But the method should be in an efficient way that you remember the equation and formula. To make this convenient for you, we have the perfect solution. 

Benefits Attached to the NCERT Solutions for Class 8 Maths Chapter 2

Significance of NCERT Solutions:

Maths is a difficult subject for so many students. On the other hand, it can be effortless for some. It depends on every individual's efficiency of understanding. To make it simple for you, NCERT Solutions have a practical list of subject experts to simplify the Class 8 Maths Chapter 2. You can obtain the free PDF downloads from our Website. 

Quality NCERT Solutions

To make sure our students are gaining better results by practising our answers for Linear Equations in One Variable Class 8, our teachers conduct a series of a questionnaire and maintain the consistency of it. 

Our Skilled Teachers Put their Efforts

The panel of experienced teachers writes all the simplified content provided in NCERT Solutions for Class 8 Maths Chapter 2 PDF. They primarily use shortcut techniques according to the standards of NCERT Solutions. 

You Score More Marks

There is no denial saying that you obtain better marks by following the simplified content of Maths Chapter 2. 

You Memorize, Understand, and Study this Material Easily

The study material at NCERT Solutions is easy to understand and stays in mind as a memory for a long time. 

All the Material at NCERT is Accurate

The helpful and simplified material at CBE NCERT Solution is entirely accurate that helps you in your exam preparation.

Content is According to NCERT Guidelines

All the subject experts have to make sure that the material is according to the guidelines provided by NCERT Solutions.


Important Topics under NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Exercise 2.1

Chapter 2 of the class 8 maths syllabus is on Linear Equations in One Variable. It is a very important chapter in mathematics that is covered in class 8 and is divided into 5 major sections. The following is a list of the important topics covered under Linear Equations in One Variable. We advise students to go through each one of these topics carefully to make sure they don’t miss out on internalising the concepts of Linear Equations in One Variable.

  • Introduction

  • Solving equations where linear expressions are on one side and numbers are on the other side of the equation

  • Applications of linear equations in one variable

  • Solving equations with variables on both the sides

  • Reducing the given equations to a simpler form

 

Important Takeaways from NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable

  • Division and multiplication of algebraic expressions with integers as coefficients

  • Common errors faced by students

  • Factorisation

  • Introduction to identities

  • Process of solving linear equations in one variable

 

Free PDF Downloads from NCERT Solutions

You can download the material for Class 8 Math "Linear Equation for One Variable (2)." It's available for free on the website.

Importance of Linear Equations in One Variable

Learning about Linear Equations helps you modularized the real phenomena that make one variable changing constantly with the other variable involved. 

How Vedantu’s NCERT Solution Help You Study and Learn in Easy Way?

Vedantu has transformed the idea of training. It produces an enormously abridged version of material so that you can absorb and master complicated theories of Maths in a more accessible manner. Study today with Vedantu and excel in your class! 

And, by registering on our site, you will keep getting the information about our classes, upcoming events, free classes, webinars, and other important updates. You can avail of all the services for free, and you can also get points by inviting your friends to the page. You can join Vedantu discussion forums from where you can make study friends and have a study together.


NCERT Solutions Class 8 Maths Chapter 2 All Exercises

Chapter 2 - Linear Equations in One Variable Exercises in PDF Format

Exercise 2.2

16 Questions with Solutions

Exercise 2.3

10 Questions with Solutions

Exercise 2.4

10 Questions with Solutions

Exercise 2.5

10 Questions with Solutions

Exercise 2.6 

7 Questions with Solutions

FAQs on NCERT Solutions for Class 8 Maths Chapter 2: Linear Equations in One Variable - Exercise 2.1

1. Where can I get NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable (EX 2.1) Exercise 2.1?

NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable (EX 2.1) Exercise 2.1 are available at India's top online learning resource, Vedantu. These solutions, which strictly comply with the most recent CBSE requirements, were created by highly certified and experienced teachers. These solutions include precise and thorough responses to every sum presented in the NCERT Mathematics textbook for Class 8. On Vedantu's official website (Vedantu.com), you may quickly and gratis download PDF versions of these study guides. You can also get the Vedantu mobile app.

2. How many Questions are there in Chapter 2 Linear Equations in One Variable Exercise 2.1?

Exercise 2.1 from Chapter 2: Linear Equations in One Variable Math consists of a total of 12 problems. In general, each question in Chapter 2 uses a single variable to teach the foundations of a linear equation. You can consult Vedantu, India's most popular online platform if you're looking for NCERT solutions for Class 8 Math. At Vedantu, all of the chapter exercises are collected in one location and solved step-by-step by a qualified teacher in accordance with the NCERT book's instructions.

3. How can I benefit from Vedantu’s NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable (EX 2.1) Exercise 2.1?

There are lots of benefits you can get from Vedantu’s NCERT solutions. Some of them are listed below:


  • By responding to these NCERT practice questions, they will be able to learn all the crucial ideas and formulae.

  • These solutions are created by experienced professionals working at Vedantu and precisely follow the CBSE curriculum.

  • Students will perform better if these solutions are presented to them in an easy-to-understand and step-by-step fashion.

  • You can download all of these solutions for free in PDF format at any time and from any location.

4. What concepts are being discussed in Class 8 Chapter 2 Linear Equations in One Variable?

Linear equations in one variable are covered in Class 8, Chapter 2. The maximum power of the variables employed in the equations is 1, making the linear equation in one variable an equation with only one variable. Any rational number can be used as the answer to this linear equation. Expressions that are linear on both sides of the equal sign may be part of this equation. We can transpose the variables from one side of the equation to the other, just like we can with integers. It is possible to simplify equations that were formed from expressions by converting them into a linear form and multiplying the expression with appropriate operators.

5. How can I review Linear Equations in One Variable, Chapter 2 from Math Class 8?

For students taking any board test or competitive exam, constant review is crucial during the preparation phase. After finishing each chapter, move on to the corresponding exercises to practice solving the corresponding problems. Up until your final exam, frequently practice those problems. You can refer to the Class 8 Math revision notes created by the subject-matter specialists at Vedantu, which will assist you in remembering the equations and distinctive characteristics of each conic section.